Cataract surgery with lens implant
Facility: Howard County Medical Center
Billing Code: 66984 (CPT)
One of the lower prices — 6 of 8 other NE hospitals charge more for the same procedure.
Black dot = this hospital, among the 9 NE hospitals with a price for this procedure. Full list below.
A fair price for a Cataract surgery with lens implant is about $533 (about 0.2× the $2,358 Medicare rate). Howard County Medical Center charges insurers about $502 — about the fair price. Located in St Paul, NE.
What each insurance company pays
Which insurers have negotiated a price with this hospital for this procedure — and which haven’t.
4 of 6 major insurers have a published price at this hospital
Crossed out = this hospital hasn’t published a negotiated price for that insurer for this procedure. It doesn’t necessarily mean they aren’t accepted — ask your insurer.
| Insurance company | Price range | vs. Medicare |
|---|---|---|
| UnitedHealthcaremajor | $487 - $1,973 | 21% |
| Blue Cross Blue Shieldmajor | $487 - $2,351 | 21% |
| Aetnamajor | $487 | 21% |
| Humanamajor | $414 | 18% |
| Ambetter (Centene) | $975 | 41% |
| Medica | $487 - $967 | 21% |
| Molina | $512 | 22% |
| Oscar Health | $853 | 36% |
| WellCare | $502 | 21% |
| + 3 smaller / regional plans | $487 - $1,017 |
Self-Pay How to get the cash price
Insurance Before you use insurance
Estimate your out-of-pocket cost
A rough estimate of what you’d pay with insurance (deductible + coinsurance) versus paying the cash price yourself.
Other Procedures at Howard County Medical Center
Compare: Cataract surgery with lens implant at other NE hospitals
- Fillmore County Hospital · Geneva $487
- Memorial Health Care Systems · Seward $494
- St Francis Memorial Hospital · West Point $579
- Valley County Health System · Ord $648
- Columbus Community Hospital, Inc · Columbus $982
- Brown County Hospital · Ainsworth $1,038
- Regional West Medical Center · Scottsbluff $1,123
- The Nebraska Medical Center · Omaha $1,340
Insurance negotiated median for the same procedure, sorted lowest first.